A non-empty array A consisting of N numbers is given. The array is sorted in non-decreasing order. The absolute distinct count of this array is the number of distinct absolute values among the elements of the array.
For example, consider array A such that:
A[0] = -5
A[1] = -3
A[2] = -1
A[3] = 0
A[4] = 3
A[5] = 6
The absolute distinct count of this array is 5, because there are 5 distinct absolute values among the elements of this array, namely 0, 1, 3, 5 and 6.
Write a function:
class Solution { public int solution(int[] A); }
that, given a non-empty array A consisting of N numbers, returns absolute distinct count of array A.
For example, given array A such that:
A[0] = -5
A[1] = -3
A[2] = -1
A[3] = 0
A[4] = 3
A[5] = 6
the function should return 5, as explained above.
Write an efficient algorithm for the following assumptions:
#include <algorithm>
int solution(vector<int> &A) {
int n = A.size();
vector<int> tmp;
for(int i=0;i<n;i++) {
tmp.push_back(abs(A[i]));
}
sort(tmp.begin(), tmp.end());
tmp.erase(unique(tmp.begin(), tmp.end()), tmp.end());
return tmp.size();
}
import java.util.*;
class Solution {
public int solution(int[] A) {
int n = A.length;
ArrayList<Integer> tmp = new ArrayList<Integer>();
for(int i=0;i<n;i++) {
tmp.add(Math.abs(A[i]));
}
HashSet<Integer> ans = new HashSet<Integer>(tmp);
return ans.size();
}
}