def solution(n):
if n % 2 == 0:
return '수박' * int(n/2)
else:
return '수박' * int((n-1)/2) + '수'
def water_melon(n):
s = "수박" * n
return s[:n]
def water_melon(n):
return "수박"*(n//2) + "수"*(n%2)
def water_melon(n):
return ("수박"*n)[0:n]