https://softeer.ai/practice/info.do?idx=1&eid=626

주어진 정보로 원하는 정보를 추출하는 단순 구현 문제이다.
List 정렬, Map 활용을 통해서 풀 수 있다.
package hello;
import java.util.*;
import java.io.*;
public class ReserveConvention {
static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
static StringTokenizer st;
static int N, M;
public static void main(String args[]) throws Exception {
st = new StringTokenizer(br.readLine());
N = Integer.parseInt(st.nextToken());
M = Integer.parseInt(st.nextToken());
boolean[][] b = new boolean[N][9];
Map<String, Integer> map = new HashMap<>();
List<String> list = new ArrayList<>();
for (int i = 0; i < N; i++) {
st = new StringTokenizer(br.readLine());
list.add(st.nextToken());
}
list.sort((o1, o2) -> o1.compareTo(o2));
for (int i = 0; i < N; i++) {
map.put(list.get(i), i);
}
for (int i = 0; i < M; i++) {
st = new StringTokenizer(br.readLine());
int tmp = map.get(st.nextToken());
int start = Integer.parseInt(st.nextToken());
int end = Integer.parseInt(st.nextToken());
for (int j = start; j < end; j++) {
b[tmp][j - 9] = true;
}
}
for (int i = 0; i < N; i++) {
for (int j = 0; j < 9; j++) {
System.out.print(b[i][j] + "\t");
}
System.out.println();
}
List<Integer[]> restList;
for (int i = 0; i < N; i++) {
bw.append("Room " + list.get(i) + ":\n");
restList = new ArrayList<>();
boolean preB = true;
int startRest = 0, endRest = 0;
for (int j = 0; j < 9; j++) {
if (!b[i][j] && preB) {
startRest = j + 9;
} else if (b[i][j] && !preB) {
endRest = j + 9;
restList.add(new Integer[]{startRest, endRest});
}
preB = b[i][j];
}
if(restList.size() == 0){
bw.append("Not avilable")
}
}
}
}