https://www.acmicpc.net/problem/10974
from itertools import permutations
n=int(input())
permus=list(permutations(range(1,n+1),n))
for permu in permus:
print(*permu)
import java.util.*;
import java.lang.*;
import java.io.*;
// The main method must be in a class named "Main".
class Main {
public static List<int[]> generatePermutations(int[] arr,int r){
List<int[]> permutations=new ArrayList<int[]>();
int[] permutation=new int[r];
boolean[] used = new boolean[arr.length];
generatePermutation(arr,0,r,permutation,used,permutations);
return permutations;
}
public static void generatePermutation(int[] arr,int index,int r,int[] permutation,boolean[] used,List<int[]> permutations){
if(index==r){
permutations.add(permutation.clone());
return;
}
for(int i=0;i<arr.length;i++){
if(!used[i]){
used[i]=true;
permutation[index]=arr[i];
generatePermutation(arr,index+1,r,permutation,used,permutations);
used[i]=false;
}
}
}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int[] arr=new int[n];
for(int i=1;i<=n;i++){
arr[i-1]=i;
}
List<int[]> permutations=generatePermutations(arr,n);
StringBuilder answer=new StringBuilder();
for(int[] permutation : permutations){
for(int k : permutation){
answer.append(k);
answer.append(" ");
}
answer.append("\n");
}
System.out.println(answer.toString());
}
}
이렇게 Python과 Java로 백준의 "모든 순열" 문제를 해결해보았습니다. 코드와 개념 설명을 참고하여 문제를 해결하는 데 도움이 되셨길 바랍니다! 😊