
Example 1:
Input: arr = [2,6,4,1]
Output: false
Explanation: There are no three consecutive odds.
for(let i = 0; i < arr.length; i++) {
if(arr[i] % 2 === 1 &&
arr[i +1] % 2 === 1 &&
arr[i +2 ] % 2 === 1 ){
return true;
}
}
return false;
};
Example 1:
Input: "USA"
Output: True
Example 2:
Input: "FlaG"
Output: False
var detectCapitalUse = function(word) {
let result = "";
let words = word.split("");
if(word === word.toUpperCase() ||
word === word.toLowerCase()){
return true;
}
if(word[0] === word.toUpperCase()[0]){
for(let i=0; i < words.length; i++){
if(words[i] === words[i].toUpperCase()){
result = result + words[i];
}
}
return result.length >1 ? false : true;
}
return false;
};
Example 1:
Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.
Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17
var maximumWealth = function(accounts) {
const result = [];
for (let i = 0; i <accounts.length; i++){
result.push(accounts[i].reduce((a,b) => a + b));
}
return Math.max(...result);
};
Example 1:
Input: nums = [2,5,1,3,4,7], n = 3
Output: [2,3,5,4,1,7]
Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7].
Example 2:
Input: nums = [1,2,3,4,4,3,2,1], n = 4
Output: [1,4,2,3,3,2,4,1]
Example 3:
Input: nums = [1,1,2,2], n = 2
Output: [1,2,1,2]
var shuffle = function(nums, n) {
let result = [];
let x =nums.slice(0, n);
let y = nums.slice(n);
for(let i = 0; i < n; i++){
result.push(x[i], y[i]);
}
return result;
};