πŸ’»ν˜• λ³€ν™˜(22.10.28 μžλ°”μˆ˜μ—…)

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μžλ°”κ³΅λΆ€κΈ°λ‘

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πŸ“Œν˜• λ³€ν™˜, νƒ€μž… λ³€ν™˜

=> μžλ°”μ˜ κΈ°λ³Έ 데이터 νƒ€μž…μ„ λ³€ν™˜
=> Booleanνƒ€μž…μ„ μ œμ™Έν•œ κΈ°λ³Έ 데이터 νƒ€μž… κ°„μ˜ λ³€ν™˜
=> μ •μˆ˜μ™€ μ‹€μˆ˜ μ—°μ‚° -> μ—°μ‚° μˆ˜ν–‰ μ•ˆλ¨
Β Β Β Β Β -> ν•˜λ‚˜μ˜ μžλ£Œν˜•μœΌλ‘œ ν†΅μΌν•œ ν›„ μ—°μ‚°

  • λ¬΅μ‹œμ  ν˜•λ³€ν™˜(μžλ™ ν˜•λ³€ν™˜)
    => μž‘μ€ 데이터 νƒ€μž…μ΄ -> 큰 데이터 νƒ€μž…μœΌλ‘œ λ³€ν™˜
    => ν˜•λ³€ν™˜μ„ λͺ…μ‹œμ μœΌλ‘œ ν•˜μ§€ μ•ŠμŒ
    => μ‹€μˆ˜ν˜•λ³€μˆ˜μ— μ •μˆ˜ν˜•λ³€μˆ˜κ°’μ„ μ €μž₯// μžλ™μœΌλ‘œ ν˜•λ³€ν™˜
    => μ‹€μˆ˜=μ •μˆ˜, ν°λ°μ΄ν„°νƒ€μž… λ³€μˆ˜ = μž‘μ€λ°μ΄ν„°νƒ€μž… λ³€μˆ˜
    byte -> short(char) -> int -> long -> float -> double
   int n=10;
   double d=n;
   System.out.println(d); //10.0

   byte a1=10;
   short a2=256;
   a2=a1;
   System.out.println(a2);

  • λͺ…μ‹œμ  ν˜•λ³€ν™˜(κ°•μ œ ν˜•λ³€ν™˜)
    => 큰 λ°μ΄ν„°νƒ€μž… -> μž‘μ€ λ°μ΄ν„°νƒ€μž…μœΌλ‘œ λ³€ν™˜
    => ν˜•λ³€ν™˜ 연산을 μ‚¬μš©ν•΄μ„œ κ°•μ œμ μœΌλ‘œ ν˜•λ³€ν™˜
    => κ°•μ œμ μœΌλ‘œ ν˜•λ³€ν™˜μ‹œ κΈ°μ‘΄ 데이터가 μ•„λ‹Œ λ‹€λ₯Έ 데이터 μ €μž₯
    => μž‘μ€λ°μ΄ν„°νƒ€μž… = (μž‘μ€λ°μ΄ν„°νƒ€μž…)ν°λ°μ΄ν„°νƒ€μž…
   double d3=3.4;
   int n2=(int) d2;   //(int)ν˜•λ³€ν™˜ μ—°μ‚°
   System.out.println(n2);  //3

   byte b1=10;
   short b2=256;
   b1=(byte) b2;  
   System.out.println(b1);
   //(byte)ν˜•λ³€ν™˜ =>μ—°μ‚° κΈ°μ–΅μž₯μ†Œλ²”μœ„ λ„˜μ–΄κ°(-128~127) => overflow
   int i=100;
   float f=i;
   System.out.println(f);


* long 8byte, float 4byte
* μ‹€μˆ˜ν˜•μ€ μ •μˆ˜ν˜•λ³΄λ‹€ 무쑰건 큰 νƒ€μž…μœΌλ‘œ μ·¨κΈ‰

long l=83983L;
float f3=l;
System.out.println(f3); ///83983.0

   float f3=3.14f;
   long l2=(long)f3;
   System.out.println(l2); //3


* byte (1), short(2) <-> char(2) ν˜•λ³€ν™˜
Β Β char ch2=65;
Β Β short sh=65;
Β Β byte by=65;
* char = byte
* byteνƒ€μž…μ˜ 음수 λ²”μœ„κ°€ char νƒ€μž…λ³΄λ‹€ 큼
* μžλ™ ν˜•λ³€ν™˜ λΆˆκ°€λŠ₯

   ch2=(char) by;
   system.out.println(ch2); //A


* char = short
* shortνƒ€μž…μ˜ 음수 λ²”μœ„κ°€ char νƒ€μž…λ³΄λ‹€ ν¬λ―€λ‘œ
* μžλ™ ν˜•λ³€ν™˜ λΆˆκ°€λŠ₯

   ch2=(char)sh;
   System.out.println(ch); //A


* ν˜• λ§žμ§€ μ•Šμ•„μ„œ μžλ™ ν˜•λ³€ν™˜ λΆˆκ°€λŠ₯

   by=(byte)ch2;
   System.out.println(by);
   sh=(short) ch2;
   System.out.println(sh);


* int = char => μžλ™μœΌλ‘œ ν˜•λ³€ν™˜

   int i3=ch2;
   System.out.println(i1);


* long(큰) = int(μž‘μ€) => μžλ™μœΌλ‘œ ν˜•λ³€ν™˜

   int i2=1234;
   long I22=i2;


* int(μž‘μ€) = long(큰) => λͺ…μ‹œμ μœΌλ‘œ ν˜•λ³€ν™˜

   i2=(int)I22;
   long l3=10000000000L;
   int i3=(int) l3;
   - λ²”μœ„κ°€ λ„˜μ–΄κ°€μ„œ μ˜€λ²„ν”Œλ‘œ λ°œμƒ μ΄μƒν•œ κ²°κ³Ό λ‚˜μ˜΄
   System.out.println(i3);

* μ£Όμ˜μ‚¬ν•­
* double => float μžλ™ ν˜•λ³€ν™˜
* κ·Όμ‚¬μΉ˜ ν‘œν˜„μ— μ˜ν•΄ 정상적이지 μ•Šμ€ 데이터가 전달
=> λΆ€μ‘±ν•œ 자릿수λ₯Ό μ±„μšΈ λ•Œ κ·Όμ‚¬μΉ˜ ν‘œν˜„μ— μ˜ν•΄ μ΄μƒν•œ κ°’ μΆ”κ°€

   float f5=1.1f;
   double d5=f5;
   System.out.println(d5); // 1.100000023841858

  • μ—°μ‚° κ³Όμ •μ—μ„œ μžλ™ ν˜•λ³€ν™˜
    => 연산을 μˆ˜ν–‰ ν•  λ•Œ 데이터 νƒ€μž…μ„ 일치 μ‹œν‚¨ ν›„ μ—°μ‚° μˆ˜ν–‰(μžλ™μœΌλ‘œ ν˜•λ³€ν™˜)
    1) int νƒ€μž…λ³΄λ‹€ μž‘μ€ νƒ€μž…λΌλ¦¬ μ—°μ‚° => intλ³€ν™˜ μ—°μ‚°
    2) int νƒ€μž…λ³΄λ‹€ 큰 νƒ€μž… μ—°μ‚° => 큰 νƒ€μž… λ³€ν™˜ μ—°μ‚°
   byte b1=10, b2=20, b3;
   System.out.println(b1+b2); //30
   * b1+b3 => byte+byte => int =>μžλ™μœΌλ‘œ ν˜•λ³€ν™˜
   * byte=(byte)int λͺ…μ‹œμ  ν˜•λ³€ν™˜
   b3=(byte)(b1+b2);
   System.out.println(b3); //30

   char ch='A';//65
   ch+3 => char +int => int =>μžλ™μœΌλ‘œ ν˜•λ³€ν™˜
   System.out.println(ch+3);//68
   char ch2=(char) (ch+3);
   System.out.println(ch2);//D

   int i1=100;
   long l1=200L;
   //int+long => long
   System.out.println(i1+l1);
   int i2=(int) (i1+l1);
   System.out.println(i2);

   float f2=0.1f
   double d2=0.1;
   * float + double => double + double => double
   * 0.20000000149011612 => κ·Όμ‚¬μΉ˜ ν‘œν˜„ => 잘λͺ»λœ κ²°κ³Ό
   System.out.println(f2+d2); // 0.20000000149011612
   // double -> float κ°•μ œμ μœΌλ‘œ λ³€ν™˜ ν›„ μ—°μ‚°
   System.out.println(f2+(float)d2); //0.2

* λ¦¬ν„°λŸ΄λΌλ¦¬μ˜ μ—°μ‚° ν˜•λ³€ν™˜ λ°œμƒ ν•˜μ§€ μ•ŠλŠ”λ‹€
   byte b5=100+20;
   // byte b6=100+30; //λ²”μœ„ λ„˜μ–΄κ°
   byte b6=(byte)(100+30);
   System.out.println(b6); //-126

   double d5=1.2;
   float f5=0.9F;
   //int i5= d5ν˜•λ³€ν™˜ +f5 int ν˜•λ³€ν™˜;
   //int i6= ν˜•λ³€ν™˜ 두 수 λ”ν•˜κΈ°;

   int i5=(int)d5+(int)f5;
   int i6=(int)(d5+f5);
   System.out.println(i5); //1
   System.out.println(i6); //2

   char ch1 = 'A';
   System.out.println((int)ch1);
   int ch3 = 67;
   System.out.println((char)ch3);

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