문제

https://programmers.co.kr/learn/courses/30/lessons/12954

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접근

반복문 응용

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코드

python

def solution(x, n):
    answer = []
    i = x
    while(len(answer) < n) :
        answer.append(x)
        x += i
        
    return answer

# x=0 일 때는 error
def solution(x, n):
    
    return [i for i in range(x, x*(n+1), x)]
    

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js

function solution(x, n) {
    var answer = [];
    
    for(var i=x; answer.length<n; i+=x){
        answer.push(i);
    }
    return answer;
}