[코테 풀이] Evaluate Boolean Binary Tree

시내·2024년 6월 15일
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Q_2331) Evaluate Boolean Binary Tree

출처 : https://leetcode.com/problems/evaluate-boolean-binary-tree/

You are given the root of a full binary tree with the following properties:

  • Leaf nodes have either the value 0 or 1, where 0 represents False and 1 represents True.
  • Non-leaf nodes have either the value 2 or 3, where 2 represents the boolean OR and 3 represents the boolean AND.

The evaluation of a node is as follows:

  • If the node is a leaf node, the evaluation is the value of the node, i.e. True or False.
  • Otherwise, evaluate the node's two children and apply the boolean operation of its value with the children's evaluations.

Return the boolean result of evaluating the root node.

A full binary tree is a binary tree where each node has either 0 or 2 children.

A leaf node is a node that has zero children.

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public boolean evaluateTree(TreeNode root) {
        if(!isLeafNode(root)){
            if(root.val==2) return evaluateTree(root.left) || evaluateTree(root.right);
            else if(root.val==3) return evaluateTree(root.left) && evaluateTree(root.right);
        }
        else if(isLeafNode(root)){
            if(root.val==1) return true;
            else if(root.val==0) return false;
        }
        return false;
    }
    
    public boolean isLeafNode(TreeNode root){
        if(root.left == null && root.right == null) return true;
        return false;
    }
}

-왁 트리문제 첨으로 풀이 참조 안 하고 풀었다^^ .. 🥸

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