SELECT a.item_id,a.item_name,a.rarity
from item_info a
left join (select distinct parent_item_id from item_tree) b
on a.item_id = b.parent_item_id
where b.parent_item_id is null
order by 1 desc
left join 해서 null 값인 row 찾기
SELECT a.item_id,a.item_name,a.rarity
from item_info a
left join item_tree b
on a.item_id = b.parent_item_id
where b.parent_item_id is null
order by 1 desc
굳이 서브쿼리로 parent_item_id만 찾을 필요가 없었다.