백준 기초부터 다시 풀어보자
https://www.acmicpc.net/problem/10828
import sys
input = sys.stdin.readline
n = int(input())
arr = []
for i in range(n):
tem = list(map(str, input().split()))
if tem[0] == "push":
arr.append(tem[1])
elif tem[0] == "pop":
if len(arr) == 0:
print(-1)
else:
print(arr.pop())
elif tem[0] == "size":
print(len(arr))
elif tem[0] == "empty":
if len(arr) == 0:
print(1)
else:
print(0)
else:
if len(arr) == 0:
print(-1)
else:
print(arr[-1])
자바 코드
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Stack;
import java.util.StringTokenizer;
public class Main {
static Stack<Integer> stack = new Stack<>();
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
for (int i = 0; i < n; i++) {
StringTokenizer st = new StringTokenizer(br.readLine());
String s = st.nextToken();
if (s.equals("push")) {
stack.push(Integer.parseInt(st.nextToken()));
}
else if (s.equals("pop")) {
if (stack.isEmpty()) {
System.out.println(-1);
} else {
System.out.println(stack.pop());
}
}
else if (s.equals("size")) {
System.out.println(stack.size());
}
else if (s.equals("empty")) {
if (stack.isEmpty()) {
System.out.println(1);
} else {
System.out.println(0);
}
}
else {
if (stack.isEmpty()) {
System.out.println(-1);
} else {
System.out.println(stack.peek());
}
}
}
}
}
자바로는 풀지 못했다...