You have a long flowerbed in which some of the plots are planted, and some are not.
However, flowers cannot be planted in adjacent plots.
Given an integer array flowerbed containing 0's and 1's, where 0 means empty and 1 means not empty, and an integer n, return true if n new flowers can be planted in the flowerbed without violating the no-adjacent-flowers rule and false otherwise.
Example 1:
Example 2:
1 <= flowerbed.length <= 2 * 10^4flowerbed[i] is 0 or 1.flowerbed.0 <= n <= flowerbed.length/**
* @param {number[]} flowerbed
* @param {number} n
* @return {boolean}
*/
var canPlaceFlowers = function(flowerbed, n) {
for (let i = 0; i < flowerbed.length && n > 0; i++) {
if (!flowerbed[i- 1] && !flowerbed[i] && !flowerbed[i+1]) {
flowerbed[i] = 1;
n--;
}
}
return n === 0;
};
You are given an m x n binary matrix grid. An island is a group of 1's (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded by water.
The area of an island is the number of cells with a value 1 in the island.
Return the maximum area of an island in grid. If there is no island, return 0.

m == grid.lengthn == grid[i].length1 <= m, n <= 50grid[i][j] is either 0 or 1./**
* @param {number[][]} grid
* @return {number}
*/
var maxAreaOfIsland = function(grid) {
const m = grid.length;
const n = grid[0].length;
let maxArea = 0;
const bfs = (rowIndex, colIndex) => {
const dx = [1, -1, 0, 0];
const dy = [0, 0, 1, -1];
let area = 0;
const queue = [[rowIndex, colIndex]];
while (queue.length) {
const [row, col] = queue.shift();
grid[row][col] = 0;
area += 1;
for (let i = 0; i < dx.length; i++) {
const nextRow = row + dx[i];
const nextCol = col + dy[i];
if (nextRow >= 0 && nextRow < m && nextCol >= 0 && nextCol < n && grid[nextRow][nextCol]) {
queue.push([nextRow, nextCol]);
grid[nextRow][nextCol] = 0;
}
}
}
return area;
};
for (let i = 0; i < m; i++) {
for (let j = 0; j < n; j++) {
if (grid[i][j]) {
maxArea = Math.max(maxArea, bfs(i, j));
}
}
}
return maxArea;
};
num consisting only of digits 6 and 9.Return the maximum number you can get by changing at most one digit (6 becomes 9, and 9 becomes 6).
Example 1:
Example 2:
1 <= num <= 10^4num consists of only 6 and 9 digits./**
* @param {number} num
* @return {number}
*/
var maximum69Number = function(num) {
const numStr = num.toString();
const maxNumStr = numStr.replace('6', '9');
return parseInt(maxNumStr);
};