https://programmers.co.kr/learn/courses/30/lessons/12922
def solution(n):
answer = ''
for i in range(1,n+1):
if i%2==1:
answer+="수"
else:
answer+="박"
return answer
def water_melon(n):
s = "수박" * n
return s[:n]
def water_melon(n):
return "수박"*(n//2) + "수"*(n%2)
def solution(n):
return "".join(["수박"[i%2] for i in range(n)])