You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the ith customer has in the jth bank. Return the wealth that the richest customer has.
A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
Example 1:
Input: accounts = [[1,2,3],[3,2,1]] Output: 6 Explanation: 1st customer has wealth = 1 + 2 + 3 = 6 2nd customer has wealth = 3 + 2 + 1 = 6 Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]] Output: 10 Explanation: 1st customer has wealth = 6 2nd customer has wealth = 10 3rd customer has wealth = 8 The 2nd customer is the richest with a wealth of 10.
Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17
Constraints:
・ m == accounts.length ・ n == accounts[i].length ・ 1 <= m, n <= 50 ・ 1 <= accounts[i][j] <= 100
사람들의 계좌가 주어지고, 각 계좌에 들어있는 예금 또한 주어진다. 이 때 가장 많은 예금을 가지고 있는 사람을 찾아, 그 계좌에 들어있는 돈의 합계를 구하라는 문제다.
모든 계좌를 뒤져 합을 구하고 가장 큰 합을 리턴하기만 하면 된다. (O(mn), m = 사람 수, n = 계좌 수)
class Solution {
public int maximumWealth(int[][] accounts) {
int res = 0;
for (int[] customer : accounts) {
int sum = 0;
for (int money : customer) {
sum += money;
}
res = Math.max(res, sum);
}
return res;
}
}