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💡 MySQL

🔗 문제

오랜 기간 보호한 동물(1) [Link]

💻 코드

SELECT INS.NAME, INS.DATETIME
FROM ANIMAL_INS AS INS
LEFT JOIN ANIMAL_OUTS AS OUTS
ON INS.ANIMAL_ID = OUTS.ANIMAL_ID
WHERE OUTS.ANIMAL_ID IS NULL
ORDER BY INS.DATETIME
LIMIT 3;