Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Input: 19 Output: true Explanation: 12 + 92 = 82 82 + 22 = 68 62 + 82 = 100 12 + 02 + 02 = 1
class Solution {
public boolean isHappy(int n) {
int sum = 0;
int length;
int cnt=0;
while (cnt<10) {
length = (int) (Math.log10(n) + 1);
for (int i = 0; i < length; i++) {
sum += Math.pow((n % 10), 2);
n /= 10;
}
System.out.println(sum);
if (sum == 1) {
return true;
} else {
n = sum;
sum = 0;
}
cnt++;
}
return false;
}
}
cnt 를 10번으로 두고 하셨는데,
10번 연산 후에 루프가 형성되는 경우도 있지않을까요?