๐Ÿงก๋ฌธ์ œ ์„ค๋ช…

์ฒซ ๋ฒˆ์งธ ๋ถ„์ˆ˜์˜ ๋ถ„์ž์™€ ๋ถ„๋ชจ๋ฅผ ๋œปํ•˜๋Š” denum1, num1, ๋‘ ๋ฒˆ์งธ ๋ถ„์ˆ˜์˜ ๋ถ„์ž์™€ ๋ถ„๋ชจ๋ฅผ ๋œปํ•˜๋Š” denum2, num2๊ฐ€ ๋งค๊ฐœ๋ณ€์ˆ˜๋กœ ์ฃผ์–ด์ง‘๋‹ˆ๋‹ค. ๋‘ ๋ถ„์ˆ˜๋ฅผ ๋”ํ•œ ๊ฐ’์„ ๊ธฐ์•ฝ ๋ถ„์ˆ˜๋กœ ๋‚˜ํƒ€๋ƒˆ์„ ๋•Œ ๋ถ„์ž์™€ ๋ถ„๋ชจ๋ฅผ ์ˆœ์„œ๋Œ€๋กœ ๋‹ด์€ ๋ฐฐ์—ด์„ return ํ•˜๋„๋ก solution ํ•จ์ˆ˜๋ฅผ ์™„์„ฑํ•ด๋ณด์„ธ์š”.


๐Ÿ’›์ œํ•œ์‚ฌํ•ญ

  • 0 <denum1, num1, denum2, num2 < 1,000

๐Ÿ’š์ž…์ถœ๋ ฅ ์˜ˆ

denum1num1denum2num2result
1234[5, 4]
9213[29, 6]

๐Ÿ’™์ž…์ถœ๋ ฅ ์˜ˆ ์„ค๋ช…

์ž…์ถœ๋ ฅ ์˜ˆ #1

  • 1 / 2 + 3 / 4 = 5 / 4์ž…๋‹ˆ๋‹ค. ๋”ฐ๋ผ์„œ [5, 4]๋ฅผ return ํ•ฉ๋‹ˆ๋‹ค.

์ž…์ถœ๋ ฅ ์˜ˆ #2

  • 9 / 2 + 1 / 3 = 29 / 6์ž…๋‹ˆ๋‹ค. ๋”ฐ๋ผ์„œ [29, 6]์„ return ํ•ฉ๋‹ˆ๋‹ค.

๐Ÿ’œ๋‚˜์˜ ํ’€์ด

function solution(denum1, num1, denum2, num2) {
    let a = denum2*num1 + num2*denum1;
    let b = num1*num2;
    let maximum = 1;
     for(let i = 1 ; i <= a ; i ++) {
        if(a%i === 0 && b%i === 0) {
            maximum = i
        }
    }
    return [a/maximum, b/maximum]
}
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