import java.io.*;
import java.sql.SQLOutput;
import java.util.*;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine());
StringTokenizer st;
List<String> tokens = new ArrayList<>();
for (int i = 0; i < n; i++) {
st = new StringTokenizer(br.readLine());
while (st.hasMoreTokens()) {
tokens.add(st.nextToken());
}
}
int[] arr = {0, 0, 0, 0};
for (int i = 0; i < tokens.size(); i += 2) {
int num = Integer.parseInt(tokens.get(i + 1));
switch (tokens.get(i)) {
case "STRAWBERRY":
arr[0] += num;
break;
case "BANANA":
arr[1] += num;
break;
case "LIME":
arr[2] += num;
break;
case "PLUM":
arr[3] += num;
break;
}
}
for (int i : arr) {
if(i == 5) {
System.out.println("YES");
return;
}
}
System.out.println("NO");
br.close();
}
}
하드코딩을 안쓰고싶었는데.. 별 수 있나..
다른 사람 풀이를 비트시프트를 쓰더라...