Given a 0-indexed integer array nums of length n and an integer k, return the number of pairs (i, j) where 0 <= i < j < n, such that nums[i] == nums[j] and (i * j) is divisible by k.

/**
* @param {number[]} nums
* @param {number} k
* @return {number}
*/
var countPairs = function(nums, k) {
let answer = 0;
for (let i = 0; i < nums.length - 1; i++) {
for (let j = i + 1; j < nums.length; j++) {
if (nums[i] === nums[j] && (i * j) % k === 0) answer++
}
}
return answer
};
너무 쉬웠당