[SQL] Occupation 문제 풀이 3

한예은·2025년 4월 6일
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문제



풀이

SELECT 
    c.company_code,
    c.founder,
    COUNT(DISTINCT lm.lead_manager_code) AS total_lead_managers,
    COUNT(DISTINCT sm.senior_manager_code) AS total_senior_managers,
    COUNT(DISTINCT m.manager_code) AS total_managers,
    COUNT(DISTINCT e.employee_code) AS total_employees
FROM Company c
LEFT JOIN Lead_Manager lm
    ON c.company_code = lm.company_code
LEFT JOIN Senior_Manager sm
    ON c.company_code = sm.company_code
LEFT JOIN Manager m
    ON c.company_code = m.company_code
LEFT JOIN Employee e
    ON c.company_code = e.company_code
GROUP BY c.company_code, c.founder
ORDER BY c.company_code;
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