# string 내 alphabet 한개라도 있으면 1리턴
def is_alpha_in_str(target) :
for ch in target :
if ch.isalpha() :
return 1
return 0
def solution(s):
answer = s
while(is_alpha_in_str(answer)) :
answer = answer.replace('one', '1')
answer = answer.replace('two', '2')
answer = answer.replace('three', '3')
answer = answer.replace('four', '4')
answer = answer.replace('five', '5')
answer = answer.replace('six', '6')
answer = answer.replace('seven', '7')
answer = answer.replace('eight', '8')
answer = answer.replace('nine', '9')
return int(answer)
시간 초과가 났다..!
def solution(s):
answer = s
num_dict = {'zero':0, 'one':1, 'two':2, 'three':3, 'four':4, 'five':5, 'six':6, 'seven':7, 'eight':8, 'nine':9}
for item in num_dict.items():
answer = answer.replace(item[0], str(item[1]))
return int(answer)
딕셔너리 아예 활용을 못하고 있었는데..
반복분 + 딕셔너리가 빠르고 깔끔하구만 🤔