플로이드 워셜 알고리즘으로 풀었으나 시간 초과로 실패..
#include <iostream>
#include <algorithm>
#include <queue>
using namespace std;
int N, M;
int answer[1001][1001];
bool visited[1001];
void bfs(int num)
{
queue<int> q;
q.push(num);
while (!q.empty())
{
int tmp = q.front();
q.pop();
int minValue = 1000000000;
int minIndex = N+1;
for (int i = 1; i <= N; i++)
{
if (i == tmp) continue;
answer[num][i] = min(answer[num][i], answer[num][tmp] + answer[tmp][i]);
if (minValue > answer[num][i] && !visited[i])
{
minValue = answer[num][i];
minIndex = i;
}
}
if (minIndex != N + 1)
{
q.push(minIndex);
visited[minIndex] = true;
}
}
}
int main()
{
cin.tie(NULL);
cout.tie(NULL);
ios_base::sync_with_stdio(false);
cin >> N >> M;
for (int i = 1; i <= N; i++)
{
for (int j = 1; j <= N; j++)
{
answer[i][j] = 1000000000;
}
}
for (int i = 0; i < M; i++)
{
int a, b, c;
cin >> a >> b >> c;
answer[a][b] = min(answer[a][b], c);
}
int start, end;
cin >> start >> end;
for (int i = 1; i <= N; i++)
{
answer[i][i] = 0;
}
bfs(start);
cout << answer[start][end];
}
다익스트라로 푸니까 완전 빠름!