You are given a string s, where every two consecutive vertical bars '|' are grouped into a pair. In other words, the 1st and 2nd '|' make a pair, the 3rd and 4th '|' make a pair, and so forth.
Return the number of '' in s, excluding the '' between each pair of '|'.
Note that each '|' will belong to exactly one pair.
Input: s = "l|*e*et|c**o|*de|"
Output: 2
Explanation: The considered characters are underlined: "l|*e*et|c**o|*de|".
The characters between the first and second '|' are excluded from the answer.
Also, the characters between the third and fourth '|' are excluded from the answer.
There are 2 asterisks considered. Therefore, we return 2.
Input: s = "iamprogrammer"
Output: 0
Explanation: In this example, there are no asterisks in s. Therefore, we return 0.
Input: s = "yo|uar|e**|b|e***au|tifu|l"
Output: 5
Explanation: The considered characters are underlined: "yo|uar|e**|b|e***au|tifu|l".
There are 5 asterisks considered.
Therefore, we return 5.
class Solution:
def countAsterisks(self, s: str) -> int:
stack= False;
answer = 0;
for i in range(len(s)):
if s[i] == '|':
stack = not stack
if s[i] == '*' and stack == False:
answer+=1
return answer
#입력 : "l|*e*et|c**o|*de|"
class Solution:
def countAsterisks(self, s: str) -> int:
ls=s.split('|')[::2] #['l', 'c**o', ''] 두개씩 끊어서 저장한다.
ans=0
for i in ls:
ans+=i.count('*')
return ans