Chap1. First Order ODEs

DalKum·2023년 6월 17일
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CONTENTS

  • Basic Concepts, Modeling
  • Direction Fields, Euler's Method ( Geometric Meaning of y,=f(x,y)y^,=f(x,y) )
  • Separable ODEs, Reduction to Separable Form
  • Exact ODEs, Integrating Fcators
  • Linear ODEs, Bernoulli Equation
  • Othogonal Trajectories
  • Existence and Uniqueness of Soultions for I.V.P.


1.1 Basic Concepts, Modeling

Mathmatical Modeling

A model is very often an equation containing derivatives of an unknown function.
Such a model is called a Differential Equation.

D.E ( Differential Equation )

  1. ODE ( Ordinary Differential Equation )
    An equation that contains one or several derivatives of an unknown function of one independent variable.
    such as y=cosxy'=cosx , y+9y=0y''+9y=0 , x2yy+2exy=(x2+2)y2x^2y'''y'+2e^xy''=(x^2+2)y^2
  2. PDE ( Partial Differential Equation )
    An equation involving partial derivatives of an unknown function of two or more variables.
    such as 2ux2+2uy2=0\frac{\partial^2 u}{\partial x^2}+\frac{\partial^2 u}{\partial y^2}=0

Solution

y=h(x)y=h(x) is called a solution if it satisfies the ODE in a given interval a<x<ba<x<b (open interval /closed interval). → explicit solution

u(x,y)=0u(x,y)=0implicit solution

Solution
1. General Solution : a solution containing an arbitrary constant ( CC ).
2. Particular Solution : a solution that we choose a specific constant ( C=3C=3 )
3. Singular Solution : an additional solution that cannot be obtained from the general solution.

such as ODE (y)2xy+y=0(y')^2-xy+y=0 ,
G.S : y=cxc2y=cx-c^2
P.S : y=2x4y=2x-4
S.S : y=x2/4y=x^2/4

Initial Value Problem (I.V.P)

General Soultion ++ Initial Conditions(I.Cs) == Particular Solution


1.3 Separable ODEs, Reduction to Separable Form

g(y)y=f(x)g(y)*y'=f(x)
: Separable Equation

Method of Separating Variables

g(y)y=f(x)g(y)*y'=f(x)
g(y)dydx=f(x)g(y)\frac{dy}{dx}=f(x)
g(y)dy=f(x)dx\int g(y) dy= \int f(x) dx
G(y)=F(x)+CG(y)=F(x)+C

Reduction to Separable Form

A homogeneous ODE y=f(yx)y'=f(\frac{y}{x}) can be reduced to separabel form by the substitution of y=uxy=ux.

y=f(yx)y'=f(\frac{y}{x})
ux+u=f(u)u'x+u=f(u)
duf(u)u=dxx\frac{du}{f(u)-u}=\frac{dx}{x}
where y=uxu=yxy=ux⇒ u=\frac{y}{x} , y=d(ux)dx=ux+uy'=\frac{d(ux)'}{dx}=u'x+u

EX)EX) 2xyy=y2x22xyy'=y^2-x^2
x2+y2=cx∴x^2+y^2=c^*x


1.4 Exact ODEs, Integrating Factors

Exact Differential Equation

A first order ODE M(x,y)+N(x,y)y=0M(x,y)+N(x,y)y'=0 , written as M(x,y)dx+N(x,y)dy=0M(x,y)dx+N(x,y)dy=0 is called an Exact Differential Equation if the differential form M(x,y)dx+N(x,y)dyM(x,y)dx+N(x,y)dy is exact, that is, this form is the differential du=uxdx+uydydu=\frac{\partial u}{\partial x}dx+\frac{\partial u}{\partial y}dy of some function u(x,y)u(x,y). Then,
M(x,y)dx+N(x,y)dy=0M(x,y)dx+N(x,y)dy=0
du=0du=0
u(x,y)=Cu(x,y)=C : implicit solution

Condition for Exactness

Necessary and sufficient condition to be an exact differential equation.

M(x,y)dx+N(x,y)dy=0M(x,y)dx+N(x,y)dy=0
du=uxdx+uydy=0du=\frac{\partial u}{\partial x}dx+\frac{\partial u}{\partial y}dy=0
dudx=M,dudy=N\frac{du}{dx}=M, \frac{du}{dy}=N
My=Nx\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x} : Condition for Exactness

How to Solve

  • Case 1
    M(x,y)=uxM(x,y)=\frac{\partial u}{\partial x}
    u(x,y)=M(x,y)dx+k(y)u(x,y)=\int M(x,y)dx+k(y)
    uy=N(x,y)\frac{\partial u}{\partial y}=N(x,y)
    dkdy\frac{dk}{dy}
    k(y)k(y)

  • Case 2
    N(x,y)=uyN(x,y)=\frac{\partial u}{\partial y}
    u(x,y)=N(x,y)dx+l(x)u(x,y)=\int N(x,y)dx+l(x)
    ux=M(x,y)\frac{\partial u}{\partial x}=M(x,y)
    dldx\frac{dl}{dx}
    l(x)l(x)

Integrating Factor

(FP)dx+(FQ)dy=0(FP)dx+(FQ)dy=0 , where FP=M,FQ=NFP=M, FQ=N
Condition for Exactness : (FP)y=(FQ)x\frac{\partial (FP)}{\partial y}=\frac{\partial (FQ)}{\partial x}

The function F(x,y)F(x,y) is the solution that depends on both x and y.

  1. F=F(x)F=F(x) : function of x only
    This function depends soley on x , Fx=F,Fy=0\frac{\partial F}{\partial x}=F′, \frac{\partial F}{\partial y}=0
    so, Conditon for Exactness be made for like
    (FP)y=(FQ)x\frac{\partial (FP)}{\partial y}=\frac{\partial (FQ)}{\partial x}
  1. F=F(y)F=F(y) : function of y only

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2023년 6월 22일

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