문제

풀이

• 무식한 방식으로 풀었지만 이게 최선의 방식인 듯 하다.

function solution(today, terms, privacies) {
    const answer = [];    

    const [todayYear, todayMonth, todayDay] = today.split('.').map((v)=> +v);  
    const expirePeriod = terms.reduce((acc, term) => {
        const [ key, val ] = term.split(' ');
        acc[key] = val*1;
        return acc;
    }, {})

    privacies.forEach((info, idx) => {
        const [date, termCode] = info.split(' ');
        const expiration = expirePeriod[termCode]*1;
        let [infoYear, infoMonth, infoDay] = date.split('.').map((v) => +v);
 
        // 각 개인정보의 만료시일 = 수집일자 + 만료기간 
        let limitYear = infoYear + Math.floor(expirePeriod[termCode] / 12); 
        let limitMonth = infoMonth + expirePeriod[termCode] % 12; 
        let limitDay = infoDay - 1;
        // console.log(`번호 : ${idx}\n오늘 날짜 : ${today}\n만료기간 : ${expiration}\n수집일자 : ${infoYear}.${infoMonth}.${infoDay}\n만료시일 : ${limitYear}.${limitMonth}.${limitDay}`)

        if (limitMonth > 12) {
            limitYear += 1
            limitMonth -= 12;
        }
        
        if (limitDay === 0) {
            limitDay = 28;
            limitMonth -= 1;
        }

        // 오늘날짜와 만료 시일 비교
        if (todayYear > limitYear) {
            answer.push(idx+1);
        } else if (todayYear === limitYear 
                   && todayMonth > limitMonth) {
            answer.push(idx+1);
        } else if (todayYear === limitYear 
                   && todayMonth === limitMonth
                   && todayDay > limitDay 
                  ) {
            answer.push(idx+1);
        }
    })
    
    return answer;
}

다른 풀이

function solution(today, terms, privacies) {
  var answer = [];
  var [year, month, date] = today.split(".").map(Number);
  var todates = year * 12 * 28 + month * 28 + date;
  var t = {};
  terms.forEach((e) => {
    let [a, b] = e.split(" ");
    t[a] = Number(b);
  });
  privacies.forEach((e, i) => {
    var [day, term] = e.split(" ");
    day = day.split(".").map(Number);
    var dates = day[0] * 12 * 28 + day[1] * 28 + day[2] + t[term] * 28;
    if (dates <= todates) answer.push(i + 1);
  });
  return answer;
}