PostgetServlet.java
package com.codingbox.servlet;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/postget")
public class PostgetServlet extends HttpServlet{
@Override
protected void service(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
if( request.getMethod().equals("GET") ) {
System.out.println("GET요청");
} else if( request.getMethod().equals("POST") ) {
System.out.println("POST요청");
}
super.service(request, response);
}
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
System.out.println("doPost 메소드 호출");
}
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
System.out.println("doGet 메소드 호출");
}
}📌 postget.jsp post버전
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
<form action="postget" method="post">
<input type="submit" value="button">
</form>
</body>
</html>💡 결과값
postget.jsp 기본 출력
버튼 클릭시 이클립스 console에 출력
📌 postget.jsp get버전
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
<form action="postget" method="get">
<input type="submit" value="button">
</form>
</body>
</html>💡 결과값
⭐️내가만든쿠키⭐️