NOT IN을 활용한 풀이SELECT ANIMAL_ID, NAME FROM ANIMAL_OUTS WHERE ANIMAL_ID NOT IN (SELECT ANIMAL_ID FROM ANIMAL_INS);
LEFT JOIN을 활용한 풀이SELECT outs.animal_id, outs.name FROM animal_outs AS outs LEFT JOIN animal_ins AS ins ON outs.animal_id = ins.animal_id WHERE ins.animal_id IS NULL;