You are climbing a staircase. It takes n steps to reach the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Input: n = 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Input: n = 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
1 <= n <= 45
// https://leetcode.com/problems/climbing-stairs/description/
int climbStairs(int n) {
if ( n==0 || n == 1) return 1;
return climbStairs(n - 2) + climbStairs(n - 1);
}
};
// https://leetcode.com/problems/climbing-stairs/description/
class Solution
{
public:
int memo[46] = {0};
int climbing_TopDown(int n)
{
if (n <= 1)
return 1;
if (memo[n] != 0)
return memo[n];
return memo[n] = climbing_TopDown(n - 1) + climbing_TopDown(n - 2);
}
int climbing_BottomUp(int n)
{
int table[46] = {0};
if (n == 0 || n == 1)
return 1;
// n=0 reutnr 1 becuase 2 = 1+1 or 2
table[0] = 1;
table[1] = 1;
for (int i = 2; i <= n; i++)
{
table[i] = table[i - 1] + table[i - 2];
}
return table[n];
}
int climbStairs(int n)
{
// pick what you want
//return climbing_BottomUp(n);
//return climbing_TopDown(n);
return 0;
}
};