You are climbing a staircase. It takes n steps to reach the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Example 1:
Input: n = 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: n = 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
Constraints:
1 <= n <= 45
class Solution {
public int climbStairs(int n) {
// int[] numOfClimbWays=new int[n+1];
int prePreWay = 1;
int preWay = 1;
int numOfWays = 0;
for (int i = 2; i <= n; i++) {
// numOfClimbWays[i]=numOfClimbWays[i-2]+numOfClimbWays[i-1];
numOfWays = prePreWay + preWay;
prePreWay = preWay;
preWay = numOfWays;
}
// return numOfClimbWays[n];
return numOfWays;
}
}