CLT(Central Limit Theorem)

deejayosamu·2025년 7월 21일

통계 기본 개념

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Convergence in distribution

Def)
XndX<=>x,limnFXn(x)=FX(x)X_n \overset{d}{\rightarrow} X <=> \forall x, \displaystyle \lim_{ n \to \infty} F_{X_n}(x)=F_X(x)

2 useful theorem)
① Continuous Mapping theorem
XndX=>g(Xn)dg(X)X_n \overset{d}{\rightarrow} X => g(X_n) \overset{d}{\rightarrow} g(X) for any continuous function gg

② Slutsky's theorem
If XndX,Ynpc1,Znpc2(c1,c2:constant),X_n \overset{d}{\rightarrow} X, Y_n \overset{p}{\rightarrow} c_1,Z_n \overset{p}{\rightarrow} c_2(c_1,c_2: constant), then YnXn+Zndc1X+c2Y_nX_n+Z_n \overset{d}{\rightarrow} c_1X+c_2

ex1) X1,...,XniidN(μ,σ2)X_1,...,X_n \overset{iid}{\sim} N(\mu, \sigma^2)
Let Tn=Xnμs/nT_n=\frac{\overline{X_n} - \mu}{s/ \sqrt{n}} where s=i(XiXn)2n1s=\sqrt{\frac{\sum_{i} (X_i-\overline{X_n})^2}{n-1}}, then TndZT_n \overset{d}{\rightarrow} Z where ZN(0,1)Z \sim N(0,1)

pf)
XnN(μ,σ2n)=>Xnμσ/nN(0,1)Tn=Xnμσ/n×σsdZ\overline{X_n} \sim N(\mu, \frac{\sigma^2}{n}) => \frac{\overline{X_n} - \mu}{ \sigma / \sqrt{n}} \sim N(0, 1) \\ T_n = \frac{\overline{X_n} - \mu}{\sigma / \sqrt{n}} \times \frac{\sigma}{s} \overset{d}{\rightarrow} Z by slutsky's theorem (σsp1)(\frac{\sigma}{s} \overset{p}{\rightarrow} 1)

CLT(Central Limit Theorem)

Suppose X1,...,XnX_1,...,X_n is a random sample from a distribution having mean:0 & variance:1, then Yn=n XndN(0,1)Y_n=\sqrt{n} \space \overline{X_n} \overset{d}{\rightarrow} N(0,1)

pf)
clt-pf

Generalization)
When X1,...,XnX_1,...,X_n is a random sample from a distribution having mean: μ\mu & variance: σ2\sigma^2,
n(Xnμ)σdN(0,1)\frac{\sqrt{n}(\overline{X_n} - \mu)}{\sigma} \overset{d}{\rightarrow} N(0,1)

pf)

Delta method

If n(Xnθ)dN(0,σ2)\sqrt{n}(X_n - \theta) \overset{d}{\rightarrow} N(0,\sigma^2), then
n(g(Xn)g(θ))dN(0,σ2g2(θ))\sqrt{n}(g(X_n) - g(\theta)) \overset{d}{\rightarrow} N(0,\sigma^2g'^2(\theta))
for g() s.t.g(θ)<,g(θ)0g() \space s.t. g''(\theta)<\infty,g'(\theta) \neq 0

pf)
delta-pf

ex1) X1,...,XniidGamma(1,λ)X_1,...,X_n \overset{iid}{\sim} Gamma(1,\lambda)
n(logXn?)dN(0,?)E(X1)=λ,Var(X1)=λ2,E(Xn)=λ,Var(Xn)=λ2nn(Xnλ)dN(0,λ2)\sqrt{n}(log \overline{X_n}-?) \overset{d}{\rightarrow} N(0,?) \\ E(X_1)=\lambda, Var(X_1)=\lambda^2, E(\overline{X_n})=\lambda, Var(\overline{X_n})=\frac{\lambda^2}{n} \\ \sqrt{n}(\overline{X_n} - \lambda) \overset{d}{\rightarrow} N(0,\lambda^2) by CLT
g(Xn)=logXn=>g(Xn)=1/Xnn(logXnlogλ)dN(0,λ2n×1λ2)g(\overline{X_n})=log \overline{X_n} => g'(\overline{X_n}) = 1/\overline{X_n} \\ \sqrt{n}(log \overline{X_n} - log \lambda) \overset{d}{\rightarrow} N(0,\frac{\lambda^2}{n} \times \frac{1}{\lambda^2})

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