Def)
X1,X2 are independent <=> {f(x1,x2)=f(x1)f(x2)p(x1,x2)=p(x1)p(x2) for all x1,x2
Corollary)
If X1,X2 are indep.,
① P(X1∈A,X2∈B)=∫B∫Af(x1,x2)dx1dx2=∫Af(x1)dx1∫Bf(x2)dx2=P(X1∈A)P(X∈B)
② f(x2∣x1)=f(x1)f(x1,x2)=f(x1)f(x1)f(x2)=f(x2)
Theorem) factorization theorem
Let X1,X2 have supports A,B respectively,
X1,X2 are independent <=> {f(x1,x2)=g(x1)h(x2)p(x1,x2)=g(x1)h(x2)
where g(x1)>0,x1∈A and h(x2)>0,x2∈B
pf)

Theorem)
The followings are equivalent
① X1,X2 are independent
② F(x1,x2)=FX1(x1)FX2(x2)
③ P(a<X1<b,c<X2<d)=P(a<X1<b)P(c<X2<d)
④ MX1,X2(t1,t2)=MX1(t1)MX2(t2)
pf)

Theorem)
If X1,X2 are independent,
E[u(x1)v(x2)]=E(u(x1))E(v(x2))
✔︎ 역은 성립하지 않음!