Suppose XXX and YYY are vector covariance matrix 설명
Linearity and bilinearity
E(aX+bY)=aE(X)+bE(Y), ∀a,b∈RE(aX+bY)=aE(X)+bE(Y),\space \forall a,b \in \mathbb{R}E(aX+bY)=aE(X)+bE(Y), ∀a,b∈R Cov(X+Y,Z)=Cov(X,Z)+Cov(Y,Z)Cov(X+Y,Z)=Cov(X,Z)+Cov(Y,Z)Cov(X+Y,Z)=Cov(X,Z)+Cov(Y,Z) Cov(X,Y+Z)=Cov(X,Y)+Cov(X,Z)Cov(X,Y+Z)=Cov(X,Y)+Cov(X,Z)Cov(X,Y+Z)=Cov(X,Y)+Cov(X,Z) For any matrices AAA and BBB, {E(AX)=AE(X)E(XB)=E(X)BCov(AX,Y)=ACov(X,Y)Cov(X,BY)=Cov(X,Y)BT\left\{\begin{matrix} E(AX)=AE(X)\\ E(XB)=E(X)B\\ Cov(AX,Y)=ACov(X,Y)\\ Cov(X,BY)=Cov(X,Y)B^T \end{matrix}\right.⎩⎪⎪⎪⎨⎪⎪⎪⎧E(AX)=AE(X)E(XB)=E(X)BCov(AX,Y)=ACov(X,Y)Cov(X,BY)=Cov(X,Y)BT
Variance matrix
Var(AX)=AVar(X)AT=Cov(AX,AX)Var(AX)=A Var(X) A^T=Cov(AX,AX)Var(AX)=AVar(X)AT=Cov(AX,AX) Var(X+b)=Var(X)Var(X+b)=Var(X)Var(X+b)=Var(X) Var(X+Y)=Var(X)+Cov(X,Y)+Cov(Y,X)+Var(Y) (CovT(X,Y)=Cov(Y,X))Var(X+Y)=Var(X)+Cov(X,Y)+Cov(Y,X)+Var(Y) \space (Cov^T(X,Y)=Cov(Y,X))Var(X+Y)=Var(X)+Cov(X,Y)+Cov(Y,X)+Var(Y) (CovT(X,Y)=Cov(Y,X)) Var(X)Var(X)Var(X) is singular <=> ∃a(≠0)∈Rp\exists a(\neq0) \in \mathbb{R}^p∃a(=0)∈Rp s.t. P(aT(X−E(X))=0)=1P(a^T(X-E(X))=0)=1P(aT(X−E(X))=0)=1 Correlation matrix Corr(X)=Cov(Xi,Xj)Var(Xi)Var(Xj)=diag(1Var(Xi))Var(X)diag(1Var(Xj))Corr(X)=\frac{Cov(X_i,X_j)}{\sqrt{Var(X_i)} \sqrt{Var(X_j)}}=diag(\frac{1}{\sqrt{Var(X_i)}}) Var(X) diag(\frac{1}{\sqrt{Var(X_j)}})Corr(X)=Var(Xi)Var(Xj)Cov(Xi,Xj)=diag(Var(Xi)1)Var(X)diag(Var(Xj)1)
Canonical Correlation For X1∈RkX_1 \in \mathbb{R}^kX1∈Rk and X2∈RmX_2 \in \mathbb{R}^mX2∈Rm, we have maxa,b,c,d Corr(cTX2+d,aTX1+d)=max1≤i≤mλi\underset{a,b,c,d}{max} \space Corr(c^T X_2+d,a^T X_1+d )=\sqrt{\underset{1 \leq i \leq m}{max} \lambda_i}a,b,c,dmax Corr(cTX2+d,aTX1+d)=1≤i≤mmaxλi where λ1,⋯ ,λm\lambda_1, \cdots, \lambda_mλ1,⋯,λm are eigenvalues of Σ22−1/2Σ21Σ11−1Σ12Σ22−1/2\Sigma_{22}^{-1/2} \Sigma_{21} \Sigma_{11}^{-1} \Sigma_{12} \Sigma_{22}^{-1/2}Σ22−1/2Σ21Σ11−1Σ12Σ22−1/2 pf)