n 번의 독립적인(independent) 베르누이 시행 중에서 성공 횟수 X=∑i=1nYi (Yi:Bernoulli r.v.)X=\sum_{i=1}^nY_i \space (Y_i:Bernoulli \space r.v.)X=∑i=1nYi (Yi:Bernoulli r.v.) PX(x)P_X(x)PX(x): xxx번 성공할 확률
pmf of XXX PX(x)=(nx)px(1−p)n−x (x=0,1,2,...,n)(0<p<1)P_X(x)=\binom{n}{x}p^x(1-p)^{n-x} \space (x=0,1,2,...,n)(0<p<1)PX(x)=(xn)px(1−p)n−x (x=0,1,2,...,n)(0<p<1) 기댓값 E(X)=npE(X)=npE(X)=np pf) 분산 Var(X)=np(1−p)Var(X)=np(1-p)Var(X)=np(1−p) pf) mgf MX(t)=E(etx)=∑x=0n(nx)etxpx(1−p)n−x=∑x=0n(nx)(pet)x(1−p)n−x=(1−p+pet)n (−∞<t<∞)M_X(t)=E(e^{tx})=\sum_{x=0}^n\binom{n}{x}e^{tx}p^x(1-p)^{n-x}=\sum_{x=0}^n\binom{n}{x}(pe^t)^x(1-p)^{n-x}=(1-p+pe^t)^n \space (-\infty<t<\infty)MX(t)=E(etx)=∑x=0n(xn)etxpx(1−p)n−x=∑x=0n(xn)(pet)x(1−p)n−x=(1−p+pet)n (−∞<t<∞)
p(x1,...,xk)=n!x1!...xk!p1x1...pkxkxi=0,1,2,...,ni=1,...,k∑i=1kxi=n0≤pi≤1, ∑i=1kpi=1p(x_1,...,x_k)=\frac{n!}{x_1!...x_k!} p_1^{x_1}...p_k^{x_k} \\ x_i=0,1,2,...,n\\ i=1,...,k \\ \sum_{i=1}^{k} x_i=n\\ 0 \leq p_i \leq 1, \space \sum_{i=1}^{k} p_i=1p(x1,...,xk)=x1!...xk!n!p1x1...pkxkxi=0,1,2,...,ni=1,...,k∑i=1kxi=n0≤pi≤1, ∑i=1kpi=1