pdf of XXX(감마분포의 특별한 케이스) f(x)=1Γ(r2)2r2xr2−1e−x2 (x>0,r>0)≡Gamma(α=r2,β=2)f(x)=\frac{1}{\Gamma(\frac{r}{2}) 2^{\frac{r}{2}}}x^{\frac{r}{2}-1}e^{ -\frac{x}{2}} \space (x>0,r>0)\\ \equiv Gamma(\alpha=\frac{r}{2},\beta=2)f(x)=Γ(2r)22r1x2r−1e−2x (x>0,r>0)≡Gamma(α=2r,β=2) 기댓값 E(X)=rE(X)=rE(X)=r pf) 분산 Var(X)=2rVar(X)=2rVar(X)=2r pf) mgf MX(t)=(1−2t)−r2 (t<12,r>0)M_X(t)=(1-2t)^{-\frac{r}{2}} \space (t<\frac{1}{2},r>0)MX(t)=(1−2t)−2r (t<21,r>0)
Theorem) 확률 변수 XXX가 카이제곱분포를 따르고, k>−r2k>-\frac{r}{2}k>−2r 라면, E(Xk)E(X^k)E(Xk)이 존재하고 E(Xk)=2kΓ(r2+k)Γ(r2)E(X^k)=\frac{2^k \Gamma(\frac{r}{2}+k)}{\Gamma(\frac{r}{2})}E(Xk)=Γ(2r)2kΓ(2r+k) pf)