//검색
String jpql = "select m from Member m where m.age > 18";
List<Member> result = em.createQuery(jpql, Member.class)
.getResultList();
실행된 SQL
select
m.id as id,
m.age as age,
m.USERNAME as USERNAME,
m.TEAM_ID as TEAM_ID
from
Member m
where
m.age>18
//Criteria 사용 준비
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Member> query = cb.createQuery(Member.class);
//루트 클래스 (조회를 시작할 클래스)
Root<Member> m = query.from(Member.class);
//쿼리 생성 CriteriaQuery<Member> cq =
query.select(m).where(cb.equal(m.get("username"), “kim”));
List<Member> resultList = em.createQuery(cq).getResultList();
//JPQL
//select m from Member m where m.age > 18
JPAFactoryQuery query = new JPAQueryFactory(em);
QMember m = QMember.member;
List<Member> list =
query.selectFrom(m)
.where(m.age.gt(18))
.orderBy(m.name.desc())
.fetch();
String sql =
“SELECT ID, AGE, TEAM_ID, NAME FROM MEMBER WHERE NAME = ‘kim’";
List<Member> resultList =
em.createNativeQuery(sql, Member.class).getResultList();

select m from Member as m where m.age > 18
select
COUNT(m), //회원수
SUM(m.age), //나이 합
AVG(m.age), //평균 나이
MAX(m.age), //최대 나이
MIN(m.age) //최소 나이
from Member m
TypedQuery<Member> query =
em.createQuery("SELECT m FROM Member m", Member.class);
Query query =
em.createQuery("SELECT m.username, m.age from Member m");
// 이름 기준
SELECT m FROM Member m where m.username=:username
query.setParameter("username", usernameParam);
// 위치 기준
SELECT m FROM Member m where m.username=?1
query.setParameter(1, usernameParam);
//페이징 쿼리
String jpql = "select m from Member m order by m.name desc";
List<Member> resultList = em.createQuery(jpql, Member.class)
.setFirstResult(10)
.setMaxResults(20)
.getResultList();
SELECT m FROM Member m [INNER] JOIN m.team t
SELECT m FROM Member m LEFT [OUTER] JOIN m.team t
select count(m) from Member m, Team t where m.username = t.name
// JPQL
SELECT m, t FROM Member m LEFT JOIN m.team t on t.name = 'A'
// SQL
SELECT m.*, t.* FROM
Member m LEFT JOIN Team t ON m.TEAM_ID=t.id and t.name='A'
// JPQL
SELECT m, t FROM Member m LEFT JOIN Team t on m.username = t.name
// SQL
SELECT m.*, t.* FROM Member m LEFT JOIN Team t ON m.username = t.name
select m from Member m where m.age > (select avg(m2.age) from Member m2)
select m from Member m where (select count(o) from Order o where m = o.member) > 0
[NOT] EXISTS (subquery): 서브쿼리에 결과가 존재하면 참
- {ALL | ANY | SOME} (subquery)
- ALL 모두 만족하면 참
- ANY, SOME: 같은 의미, 조건을 하나라도 만족하면 참
[NOT] IN (subquery): 서브쿼리의 결과 중 하나라도 같은 것이 있으면 참
예) 팀A 소속인 회원
select m from Member m where exists (select t from m.team t where t.name = ‘팀A')
select o from Order o where o.orderAmount > ALL (select p.stockAmount from Product p)
select m from Member m where m.team = ANY (select t from Team t)
JPA 서브 쿼리 한계
- JPA는 WHERE, HAVING 절에서만 서브 쿼리 사용 가능
- SELECT 절도 가능(하이버네이트에서 지원)
- FROM 절의 서브 쿼리는 현재 JPQL에서 불가능
- 조인으로 풀 수 있으면 풀어서 해결
-> 하이버네이트6 부터는 FROM 절의 서브쿼리를 지원
select
case when m.age <= 10 then '학생요금'
when m.age >= 60 then '경로요금'
else '일반요금'
end
from Member m
select
case t.name
when '팀A' then '인센티브110%'
when '팀B' then '인센티브120%'
else '인센티브105%'
end
from Team t
// 사용자 이름이 없으면 이름 없는 회원을 반환
select coalesce(m.username,'이름 없는 회원') from Member m
// 사용자 이름이 ‘관리자’면 null을 반환하고 나머지는 본인의 이름을 반환
select NULLIF(m.username, '관리자') from Member m
select function('group_concat', i.name) from Item i
[인프런] 자바 ORM 표준 JPA 프로그래밍 - 김영한