백준 17837

SJ Lee·2022년 2월 23일
0
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#include<iostream>
#include<vector>
 
#define endl "\n"
#define MAX 12
#define CHESS_MAX 10
using namespace std;
 
struct CHESS
{
    int x;
    int y;
    int dir;
};
 
int N, K, Answer;
int MAP[MAX][MAX];
vector<int> MAP_State[MAX][MAX];
CHESS Chess[CHESS_MAX];
 
int dx[] = { 0, 0, 0, -1, 1 };
int dy[] = { 0, 1, -1, 0, 0 };
 
void Print()
{
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            cout << MAP_State[i][j].size() << " ";
        }
        cout << endl;
    }
    cout << "#######################################################################" << endl;
}
void Input()
{
    cin >> N >> K;
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            cin >> MAP[i][j];
        }
    }
    for (int i = 0; i < K; i++)
    {
        int x, y, d; cin >> x >> y >> d;
        x--; y--;
        Chess[i] = { x, y, d };
        MAP_State[x][y].push_back(i);
    }
}
 
int Find_Delete_Num(int x, int y, int Chess_Num)
{
    /* 해당 말을 옮긴 후, 기존 좌표에서 몇 번 삭제를 해야 하는지 찾는 함수. */
    int Cnt = 0;
    for (int i = MAP_State[x][y].size() - 1; i >= 0; i--)
    {
        if (MAP_State[x][y][i] == Chess_Num) break;
        Cnt++;
    }
    return Cnt + 1;
}
 
int Reverse_Dir(int Num)
{
    int Dir = Chess[Num].dir;
    if (Dir == 1) return 2;
    else if (Dir == 2) return 1;
    else if (Dir == 3) return 4;
    else if (Dir == 4) return 3;
}
 
void MoveChess(int x, int y, int nx, int ny, int Chess_Num, int Pos, int Ms)
{
    if (Ms == 0)
    {
        for (int i = Pos; i < MAP_State[x][y].size(); i++)
        {
            MAP_State[nx][ny].push_back(MAP_State[x][y][i]);
            int Idx = MAP_State[x][y][i];
            Chess[Idx].x = nx;
            Chess[Idx].y = ny;
        }
        int Delete_Num = Find_Delete_Num(x, y, Chess_Num);
        for (int i = 0; i < Delete_Num; i++) MAP_State[x][y].pop_back();
    }
    else if (Ms == 1)
    {
        for (int i = MAP_State[x][y].size() - 1; i >= Pos; i--)
        {
            MAP_State[nx][ny].push_back(MAP_State[x][y][i]);
            int Idx = MAP_State[x][y][i];
            Chess[Idx].x = nx;
            Chess[Idx].y = ny;
        }
        int Delete_Num = Find_Delete_Num(x, y, Chess_Num);
        for (int i = 0; i < Delete_Num; i++) MAP_State[x][y].pop_back();
    }
    else if (Ms == 2)
    {
        int Dir = Reverse_Dir(Chess_Num);
        Chess[Chess_Num].dir = Dir;
        int nnx = x + dx[Dir];
        int nny = y + dy[Dir];
        
        if (nnx >= 0 && nny >= 0 && nnx < N && nny < N)
        {
            if (MAP[nnx][nny] != 2) MoveChess(x, y, nnx, nny, Chess_Num, Pos, MAP[nnx][nny]);
        }
    }
}
 
int Find_Position(int x, int y, int Idx)
{
    /* 해당 말이 몇 번째에 위치하고 있는지 찾아서 return 하는 함수. */
    for (int i = 0; i < MAP_State[x][y].size(); i++)
    {
        if (MAP_State[x][y][i] == Idx) return i;
    }
}
 
bool Check_State()
{
    for (int i = 0; i < K; i++)
    {
        int x = Chess[i].x;
        int y = Chess[i].y;
        if (MAP_State[x][y].size() >= 4) return true;
    }
    return false;
}
 
void Solution()
{
    bool Flag = false;
    int Time = 0;
    while (1)
    {
        if (Time > 1000) break;
 
        for (int i = 0; i < K; i++)
        {
            int x = Chess[i].x;
            int y = Chess[i].y;
            int dir = Chess[i].dir;
 
            int nx = x + dx[dir];
            int ny = y + dy[dir];
 
            int Pos = Find_Position(x, y, i);
            if (nx >= 0 && ny >= 0 && nx < N && ny < N) MoveChess(x, y, nx, ny, i, Pos, MAP[nx][ny]);            
            else MoveChess(x, y, nx, ny, i, Pos, 2);
 
            if (Check_State() == true)
            {
                Flag = true;
                break;
            }
        }
        if (Flag == true) break;
        Time++;
    }
 
    if (Flag == true) cout << Time + 1 << endl;
    else cout << -1 << endl;
}
 
void Solve()
{
    Input();
    Solution();
}
 
int main(void)
{
    ios::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
 
    Solve();
 
    return 0;
}
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