LeetCode - Majority Element II(229)

Sorting - Medium

class Solution:
    def majorityElement(self, nums: List[int]) -> List[int]:
        standard = len(nums) // 3
        answer = []
        frequency = list(collections.Counter(nums).items())
        
        for i in range(len(frequency)):
            if frequency[i][1] > standard:
                answer.append(frequency[i][0])
        
        return answer