있었는데요 없었습니다

https://programmers.co.kr/learn/courses/30/lessons/59043

SELECT INS.ANIMAL_ID ,
       INS.NAME
FROM ANIMAL_INS AS INS INNER JOIN ANIMAL_OUTS AS OUTS ON OUTS.ANIMAL_ID = INS.ANIMAL_ID
WHERE INS.DATETIME > OUTS.DATETIME
# GROUP BY
ORDER BY INS.DATETIME