Why sufficient statistic is good?

deejayosamu·2025년 8월 4일

통계 기본 개념

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UMVUE should be a function of sufficient statistic

Theorem) Rao-Blackwell theorem
Let WW be any unbiased estimator of τ(θ)\tau(\theta), and TT be a sufficient statistic for θ\theta.
If we define ϕ(T)=E(WT),\phi(T)=E(W|T), then Eθ(ϕ(T))=τ(θ)E_\theta (\phi(T))=\tau(\theta) and Vθ(ϕ(T))Vθ(W)V_\theta (\phi(T)) \leq V_\theta(W)
pf)
rao-blackwell-pf

Theorem) Uniqueness of UMVUE
If WW is a UMVUE of τ(θ),\tau(\theta), then WW is unique.
pf)
unique.umvue-pf

Theorem)
If E(W)=τ(θ),E(W)=\tau(\theta),
WW is the UMVUE of τ(θ)\tau(\theta) <=> WW is uncorrelated with all unbiased estimator of zero
pf)
umvue-pf

How to construct UMVUE

Theorem) Lehmann-Scheffe theorem
If TT is CSS for θ\theta and E(ϕ(T))=τ(θ),E(\phi(T))=\tau(\theta), then
ϕ(T)\phi(T) is the MVUE for τ(θ)\tau(\theta)
pf)
lehmann-scheffe-pf

  • How to construct UMVUE when TT which is CSS is given
    ① Choose any unbiased estimator WW of τ(θ)\tau(\theta)
    ② Construct E(WT)E(W|T)

ex1) X1,...,XniidPoisson(λ),X_1,...,X_n \overset{iid}{\sim} Poisson(\lambda), UMVUE of eλ=P(X1=0)?e^{-\lambda}=P(X_1=0)?
make-umvue-ex1

ex2) X1,...,XniidExp(λ),X_1,...,X_n \overset{iid}{\sim} Exp(\lambda), UMVUE of e1θ=P(X1>1)?e^{-\frac{1}{\theta}}=P(X_1>1)?
make-umvue-ex2

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