[Linear Algebra] Geometric Interpretation of Least Squares

Jason Lee·2022년 9월 19일
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Linear Algebra

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Geometric Interpolation of Least Squares

  • The vector b\textbf{b} is closer to Ax^A \hat{\textbf{x}} than to AxA \textbf{x} for other x\textbf{x}
  • To satisfy this, the vector bAx^\textbf{b} - A \hat{\textbf{x}} should be orthogonal to ColA\textrm{Col} A
    • This means bAx^\textbf{b} - A \hat{\textbf{x}} should be orthogonal to any vector in ColA\textrm{Col} A
  • bAx^x1a1+x2a2++xnan\textbf{b} - A \hat{\textbf{x}} \perp x_1\textbf{a}_1 + x_2\textbf{a}_2 + \cdots + x_n\textbf{a}_n for any vector x\textbf{x}
    • Or equivalently, AT(bAx^)=0A^T (\textbf{b} - A \hat{\textbf{x}}) = \textbf{0}
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